150=-4.9x^2+60x+3

Solution for 150=-4.9x^2+60x+3 equation:

150=-4.9x^2+60x+3

We move all terms to the left:

150-(-4.9x^2+60x+3)=0

We get rid of parentheses

4.9x^2-60x-3+150=0

We add all the numbers together, and all the variables

4.9x^2-60x+147=0

a = 4.9; b = -60; c = +147;
Δ = b2-4ac
Δ = -602-4·4.9·147
Δ = 718.8
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-60)-\sqrt{718.8}}{2*4.9}=\frac{60-\sqrt{718.8}}{9.8}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-60)+\sqrt{718.8}}{2*4.9}=\frac{60+\sqrt{718.8}}{9.8}
$